Hey math people, if they all selected 1 of the 2 main candidates for every election, and they all selected different candidates, how many historians would it take to cover every combination for 10 years? (bonus points to see how many would take before guaranteeing someone could get 9/10)
1024 historians assuming they all pick different combinations at random. Probability of randomly guessing at least 9 of 10 goes up to 1.075% or 93 historians (on average to get one person with 9/10 predictions right) or like the other commenter mentioned 1024-11= 1013 to guarantee a 9/10 but that’s a little overkill.
Note that many of those elections were easier to guess than just flipping a coin, so you don’t really need to cover every potential combination to cover like 95% of the likely outcomes.
Hey math people, if they all selected 1 of the 2 main candidates for every election, and they all selected different candidates, how many historians would it take to cover every combination for 10 years? (bonus points to see how many would take before guaranteeing someone could get 9/10)
1024 historians assuming they all pick different combinations at random. Probability of randomly guessing at least 9 of 10 goes up to 1.075% or 93 historians (on average to get one person with 9/10 predictions right) or like the other commenter mentioned 1024-11= 1013 to guarantee a 9/10 but that’s a little overkill.
Where does the 93 come from? The percentage is almost correct, but it should be 11 (1.074%)
93 for 1/0.01075
Note that many of those elections were easier to guess than just flipping a coin, so you don’t really need to cover every potential combination to cover like 95% of the likely outcomes.